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find the larger of two consecutive odd integers if the larger is 20 less than three times the smaller

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Answer:

Let x be the smaller odd integer. Then the larger odd integer is x+2.

We are given that the larger integer is 20 less than three times the smaller integer. This can be expressed as an equation:

x+2 = 3x-20

Solving for x, we get:

2x = 22

x = 11

Therefore, the smaller integer is 11 and the larger integer is 13.

Here is a summary of the solution:

Smaller integer: 11

Larger integer: 13

Explanation:

User MintyAnt
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