Answer:
If 4 moles of Na reacts with 1 mole of O2 to produce 2 moles of Na2O, then:
1 mole of Na would react with 1/4 moles of O2 to produce 1/2 moles of Na2O.
Since the reaction is with excess O2, we can assume that there is enough O2 to react with the 2.50 moles of Na. Therefore, the number of moles of Na2O produced would be:
2.50 moles Na * (1/4) moles O2 * (1/2) moles Na2O = 0.3125 moles Na2O
Therefore, 0.3125 moles of sodium oxide will be produced when sodium reacts completely with excess oxygen.