Question

Pure acid is to be added to a 10% acid solution to obtain 90L of 84% solution. How many liter of 10% solution should be in the mixture?

Answer 1

16 liters of the 10% acid solution should be in the mixture.

Explanation:

Let x represent the volume of the 10% acid solution to be added.

The volume of pure acid added would be (90 - x).

The equation to solve is: 0.1x + (90 - x) = 0.84(90)

Simplifying, we get: 0.1x + 90 - x = 75.6

Combining like terms, we have: -0.9x + 90 = 75.6

Subtracting 90 from both sides: -0.9x = -14.4

Dividing by -0.9: x = 16

Therefore, 16 liters of the 10% acid solution should be in the mixture.