Answer:
Lithium Reaction: Hydrogen Moles
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The alkali metal lithium reacted with water. Calculate how many grams, moles of hydrogen were released if 56 g of lithium reacted?
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To calculate the number of grams and moles of hydrogen released when 56 g of lithium reacts with water, we need to determine the balanced chemical equation for the reaction.
The balanced chemical equation for the reaction between lithium and water is:
2 Li + 2 H₂O -> 2 LiOH + H₂
From the equation, we can see that 2 moles of lithium react to produce 1 mole of hydrogen gas.
Now, let's calculate the moles of lithium in 56 g of lithium using its molar mass:
Molar mass of lithium (Li) = 6.94 g/mol
Moles of lithium = Mass of lithium / Molar mass of lithium
= 56 g / 6.94 g/mol
≈ 8.06 mol
Since 2 moles of lithium produce 1 mole of hydrogen, we can calculate the moles of hydrogen produced:
Moles of hydrogen = (Moles of lithium) / 2
= 8.06 mol / 2
= 4.03 mol
Finally, we can calculate the grams of hydrogen using the molar mass of hydrogen:
Molar mass of hydrogen (H₂) = 2.02 g/mol
Grams of hydrogen = Moles of hydrogen × Molar mass of hydrogen
= 4.03 mol × 2.02 g/mol
≈ 8.15 g
Therefore, when 56 g of lithium reacts with water, approximately 4.03 moles (or 8.15 grams) of hydrogen gas are released.