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4(-2)² + 8(-2) + 3(-2) + 6 = ? Can you break down how you solved it

User Keen
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Answer:

Explanation:

To solve the expression 4(-2)² + 8(-2) + 3(-2) + 6, we need to follow the order of operations, which is also known as PEMDAS (Parentheses, Exponents, Multiplication and Division - from left to right, Addition and Subtraction - from left to right).

First, we will simplify any calculations within parentheses:

4(-2)² + 8(-2) + 3(-2) + 6

(-2)² is equal to (-2) * (-2), which is 4:

4 * 4 + 8(-2) + 3(-2) + 6

Next, we perform the multiplication:

4 * 4 = 16

Now, we have:

16 + 8(-2) + 3(-2) + 6

Next, we continue with the multiplication:

8(-2) = -16

3(-2) = -6

Now, we have:

16 + (-16) + (-6) + 6

Finally, we simplify the addition and subtraction from left to right:

16 + (-16) = 0

0 + (-6) = -6

-6 + 6 = 0

Therefore, the expression 4(-2)² + 8(-2) + 3(-2) + 6 simplifies to 0.

User Easy
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