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Determine: minimum, maximum, median, 1st quartile, and 3rd quartile

10,12,7,9,4,15,20,21

Minimum: _____
Maximum:_____
Median:_______
1st Quartile:____
3rd quartile:____

1 Answer

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The minimum is the smallest value in the data set:

Minimum: 4

The maximum is the largest value in the data set:

Maximum: 21

The median is the middle value in the data set. Since there are an even number of values in this data set, we take the average of the two middle values:

Median: (10 + 12)/2 = 11

To find the quartiles, we first need to find the median of the lower half and upper half of the data set:

Lower half: 4, 7, 9, 10

Upper half: 12, 15, 20, 21

Median of lower half: (7 + 9)/2 = 8

Median of upper half: (15 + 20)/2 = 17.5

The first quartile (Q1) is the median of the lower half of the data set:

1st Quartile: 8

The third quartile (Q3) is the median of the upper half of the data set:

3rd Quartile: 17.5

Therefore: Minimum: 4 Maximum: 21 Median: 11 1st Quartile: 8 3rd Quartile: 17.5

I hope this helps! Let me know if you have any other questions.

User Pyano
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