Question

How many ways can you arange 2 Letters picked
from A, B, C, D? order matters

Answer 1

Explanation:

When selecting 2 letters from the set {A, B, C, D} and considering that the order matters, we can determine the number of possible arrangements using the concept of permutations.

The number of ways to arrange 2 letters from a set of 4 can be calculated using the formula for permutations:

P(n, r) = n! / (n - r)!

where P(n, r) represents the number of permutations of r objects chosen from a set of n objects.

In this case, we have n = 4 (the total number of letters) and r = 2 (the number of letters to be selected).

Using the formula, we can calculate:

P(4, 2) = 4! / (4 - 2)!

= 4! / 2!

= (4 × 3 × 2 × 1) / (2 × 1)

= 24 / 2

= 12

Therefore, there are 12 different ways to arrange 2 letters chosen from the set {A, B, C, D} when the order matters.

Answer 2

When selecting 2 letters from the set {A, B, C, D}, considering that the order matters, we can use the concept of permutations to calculate the number of possible arrangements.

The number of ways to arrange 2 letters from a set of 4 can be calculated using the formula for permutations:

P(n, r) = n! / (n - r)!

Where n is the total number of items (in this case, 4) and r is the number of items being selected (in this case, 2).

Using this formula, the number of ways to arrange 2 letters from A, B, C, D is:

P(4, 2) = 4! / (4 - 2)!

= 4! / 2!

= (4 x 3 x 2 x 1) / (2 x 1)

= 24 / 2

= 12

Therefore, there are 12 possible ways to arrange 2 letters selected from A, B, C, D when considering that the order matters.

~~~Harsha~~~