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Out of a pool of 26 men and 29 women what is the probability that 6 men and 6 women will be selected?

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Let's evaluate the probability based on the given information.

The number of ways to choose 6 men from 26 can be calculated as:

C(26, 6) = 26! / (6! * (26-6)!) = 26! / (6! * 20!) = 230,230.

The number of ways to choose 6 women from 29 can be calculated as:

C(29, 6) = 29! / (6! * (29-6)!) = 29! / (6! * 23!) = 177,100.

The total number of possible outcomes is the combination of selecting 6 men and 6 women from the given pool of 26 men and 29 women:

Total outcomes = C(26, 6) * C(29, 6) = 230,230 * 177,100 = 40,795,315,300.

Therefore, the probability of selecting exactly 6 men and 6 women from the given pool is:

Probability = 1 / Total outcomes = 1 / 40,795,315,300 ≈ 2.45 x 10^-11.

Hence, the probability is approximately 2.45 x 10^-11.

User Benjamin Wohlwend
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