126k views
4 votes
Find the area of the triangle whoose side are 12,16 and 21 units

1 Answer

5 votes

Answer:


A = 95.45

Explanation:


A=s(s﹣a)(s﹣b)(s﹣c)


s=a+b+c

Solving for A

A=1

4﹣
a4+2(ab)2+2(ac)2﹣b4+2(bc)2﹣c4=1

4-
124+2·(12·16)2+2·(12·21)2﹣164+2·(16·21)2﹣214≈95.45123

≈ 95.45123

User Timshutes
by
8.3k points