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6ab + 2ac + 3db+ dc needs to be factorized
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6ab + 2ac + 3db+ dc needs to be factorized

User Driftavalii
by
7.8k points

1 Answer

2 votes

Answer:

Explanation:

6ab+2ac+3db+dc

Taking 2a common in the first 2 terms and d common in the next 2 terms, we get---

=>2a(3b+c)+d(3b+c)

=>(3b+c)(2a+d)------Answer!

User Vsevolod Timchenko
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8.0k points
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