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4 votes
Triangle JKL has vertices at the points J(2.5,3), K(3.2,-4.7), and L(-6.9,3). Find the slope of side JL.

A. undefined
B. -11
C. -0.76
D. 0

2 Answers

2 votes
To find the slope of a line segment between two points (x1, y1) and (x2, y2), we can use the formula:

slope = (y2 - y1) / (x2 - x1)

Let's calculate the slope of side JK first, using the coordinates of points J(2.5, 3) and K(3.2, -4.7):

slope_JK = (-4.7 - 3) / (3.2 - 2.5)
slope_JK = (-7.7) / (0.7)
slope_JK ≈ -11

Now, let's calculate the slope of side KL, using the coordinates of points K(3.2, -4.7) and L(-6.9, 3):

slope_KL = (3 - (-4.7)) / (-6.9 - 3.2)
slope_KL = (7.7) / (-10.1)
slope_KL ≈ -0.76

Therefore, the slope of side JK is approximately -11, and the slope of side KL is approximately -0.76.

The options provided are:
A. undefined
B. -11
C. -0.76
D. 0

Based on the calculations, the correct answer would be:

B. -11
User Trnc
by
8.5k points
5 votes
Hence : C is correct !
User Alind Billore
by
8.3k points