Question

I need the answer asap

A man who weighs 75 kg is on the surface of the earth. If the mass of the earth is 6x10^24 kg and its radius 6380 km, calculate the force of attraction between them.

`mass \: of \: the \: earth \: = 6 * {10}^(24)`

[Ans: 737.47 N]
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Answer 1

The force of attraction between the two objects can be calculated using Newton's Law of Universal Gravitation:
F = G m1m2 /r^2
where G is the gravitational constant (6.67x10^-11 Nm^2/Kg^2) m1 is the mass of the man (75 kg) m2 is the mass of the earth (6x10^24 kg) and r is the radius of the earth (6380 km).
Therefore, F = (6.67x10^-11 Nm^2/Kg^2) x (75 kg) x (6x10^24 kg) / (6380 km)^2 = 737.47 N