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Pls help it’s 9th grade math

Pls help it’s 9th grade math-example-1
User Nita
by
8.4k points

2 Answers

5 votes

Answer:

A) 23.7°

Explanation:

You can use the law of sines to solve this, sinA/a= sinC/c

sin42/5= sinC/3

User Kaushal Sachan
by
7.8k points
5 votes

Answer:

option A

Explanation:

To find the ∠C, we can use the Law of Sine.


\sf \boxed{(a)/(Sin \ A)=(b)/(Sin \ B)=(c)/( Sin \ C)}

Side 'a' faces ∠A, side 'b' faces ∠B and side 'c' faces ∠C

a = 5 cm ; b = 7 cm ; c = 3 cm

∠A = 42°


\sf (a)/(Sin \ A) = (c)/(Sin \ C)\\\\\\(5)/(Sin \ 42)=(3)/(Sin \ C)\\\\\\Cross \ multiply,\\\\ 5*Sin C = 3*Sin \ 42\\\\~~~~ Sin \ C = (3*Sin \ 42)/(5)\\\\


\sf = (3*0.6691)/(5)

= 0.4014

C = arcsin (0.4014)

C = 23.67

∠C = 23.7°

User Leon Yin
by
8.4k points

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