Question

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Analyze the graph to describe the solubility of barium nitrate,Ba(NO₃)₂.

At 60°C, ✔ 200 g must be added to 1 L of
water to make a saturated solution.

At 25°C, the solubility is about ✔ 100 g per liter.

A solution that contains 600 g Ba(NO₃)₂. in
3 L of H2O at 70°C is ✔ unsaturated.

For a solution that contains 300 g Ba(NO₃)₂ in 3 L of H₂O at 60°C to become saturated, ✔ 300 g
solute must be added.

Answer 1

Yes, the solubility information provided in the graph can be summarized as follows:

• 1. At 60°C, a saturated solution of barium nitrate (Ba(NO₃)₂) requires 200 g to be added to 1 L of water. This means that at this temperature, the maximum amount of Ba(NO₃)₂ that can dissolve in 1 L of water is 200 g.

• 2. At 25°C, the solubility of Ba(NO₃)₂ is approximately 100 g per liter. This indicates that at this lower temperature, a smaller amount of Ba(NO₃)₂ can dissolve in 1 L of water compared to the solubility at 60°C.

• 3. A solution that contains 600 g of Ba(NO₃)₂ in 3 L of water at 70°C is classified as unsaturated. This means that the amount of Ba(NO₃)₂ in the solution is below the maximum solubility at that temperature.

• 4. For a solution that contains 300 g of Ba(NO₃)₂ in 3 L of water at 60°C to become saturated, an additional 300 g of the solute must be added. This implies that the current solution is not saturated, as it has not reached the maximum solubility at that temperature.

In summary, the solubility of barium nitrate (Ba(NO₃)₂) increases with temperature, with higher temperatures allowing for more solute to dissolve in the solvent (water).

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