Answer:
1) = approximately 74 km/hr
2) = 9:30 AM
3) Avg speed = 28 km/hr
vel = 0.
Step-by-step explanation:
Here is how you do it:
1) To find the student's speed, we can use the formula:
Speed = Distance / Time
The student traveled a total distance of 40 km south and 15 km north, which gives a total distance of 40 km + 15 km = 55 km. The total time of travel was 0.75 hours.
Speed = 55 km / 0.75 hr ≈ 73.33 km/hr
Therefore, the student's speed is approximately 73.33 km/hr or 74 km/hr.
To calculate the student's velocity, we need to consider both magnitude and direction. Since the student ended up at the same position as the starting point, the displacement is zero. Therefore, the velocity is also zero.
2) The distance between Houston and Austin is 190 miles. The bus is traveling at a constant speed of 54.3 miles/hour. We can use the formula:
Time = Distance / Speed
Time = 190 miles / 54.3 miles/hour ≈ 3.50 hours
The bus will arrive in Austin approximately 3.50 hours after leaving Houston.
If the bus leaves Houston at 6:00 am, it will arrive in Austin around 9:30 am.
3) The girl rode 5 km east and then turned around and rode 2 km west. The total distance traveled is 5 km + 2 km = 7 km. The entire trip took fifteen minutes, which is equal to 15/60 = 0.25 hours.
Average Speed = Total Distance / Total Time
Average Speed = 7 km / 0.25 hr = 28 km/hr
Therefore, the girl's average speed is 28 km/hr.
To calculate the girl's velocity, we need to consider both magnitude and direction. The girl's initial direction was east, and her final direction was west. Since the starting and ending points are the same, the displacement is zero. Therefore, the velocity is also zero.