Question

an object in free fall near the surface of the earth accelerates at a rate of 78979.4 mi/hr2. what is the rate of acceleration for a free falling object near the surface of the earth in ft/s2 and m/s2.

Answer 1

Step-by-step explanation:

These are just simple unit conversion problems:

78979.4 mi /hr^2 * 5280 ft / mile * hr^2 / (3600 s )^2 = 32.18 ft/s^2

78979.4 mi / hr^2 * 1609.344 m / mile * hr^2 / 3600s)^2 = 9.81 m/ s^2