Question

two red balls and two green balls are placed in a bag. if you take two of the balls out of the bag without replacement, what is the probability that both balls are red? (enter your probability as a fraction.)

Answer 1

1/6

Explanation:

2 red + 2 green = 4 balls

P(1st red) = 2/4

now there's one less red in there and one less ball in total

P(2nd red) = 1/3

P(both red) = 2/4 X 1/3 = 2/12 = 1/6