Answer:
Step-by-step explanation:
(a) To find the magnitude of the electric field (E) that exerts a force on an electron, we can use the equation:
F = q * E
where F is the force exerted on the electron, q is the charge of the electron (approximately -1.6 × 10^-19 C), and E is the electric field.
Substituting the given values into the equation, we have:
5.6 × 10^-17 N = -1.6 × 10^-19 C * E
Solving for E, we get:
E = (5.6 × 10^-17 N) / (-1.6 × 10^-19 C)
E ≈ -3.5 × 10^2 N/C (magnitude)
The magnitude of the electric field that exerts the force is approximately 3.5 × 10^2 N/C.
(b) The negative sign indicates that the electric field is directed opposite to the force. Therefore, the direction of the electric field is to the west.
(c) If the electron is replaced by a proton, the magnitude of the force (F) exerted can be calculated using the same equation:
F = q * E
For a proton, the charge is the same as the electron but with a positive sign (+1.6 × 10^-19 C). Substituting this value and the magnitude of the electric field (3.5 × 10^2 N/C) into the equation, we have:
F = (1.6 × 10^-19 C) * (3.5 × 10^2 N/C)
F ≈ 5.6 × 10^-17 N
The magnitude of the force exerted on the proton is approximately 5.6 × 10^-17 N.
(d) The force on the proton will be in the same direction as the electric field, which is to the west.