Question

a motorcycle has a constant acceleration of 2.88 m/s2. both the velocity and acceleration of the motorcycle point in the same direction. how much time is required for the motorcycle to change its speed from (a)33.1 to 43.1 m/s, and (b)63.1 to 73.1 m/s?

Answer 1

Using the formula:
a = (Vf - Vi) / t
Solve for t:
t = (Vf - Vi) / a
Part A:
Substitute in the equation above
Vf = 43.1 and Vi = 33.1 and a = 2.88
t = (43.1 - 33.1) / 2.88 = 3.5 seconds

Part B
Same as part A
Vf = 73.1 and Vi= 63.1 and a=2.88
t = (73.1 - 63.1) / 2.88 = 3.5 seconds

Hope this helps