Question

What are the exact solutions of x2 - 5x-7= 0, where

Ox=
O
x=
X
H
-5± √3
2
5+√3
2
-5± √53
2
5± √53
2
X=
-b± √b²-4ac7
2a

Answer 1

Hello !

Answer:

`\large \boxed{\sf x= (5\pm\pl√(53))/(2) }`

Explanation:

This equation is a quadratic equation in the form ax²+bx+c=0

The solution of this equation is given by the quadratic formula :

`\sf x=(-b\pm√(b^2-4ac))/(2a)`

Here we have :

• a = 1
• b = +5
• c = -7

Let's replace a, b and c with their values in the quadratic formula :

`\sf x=(-(-5)\pm√((-5)^2-4*1*(-7)))/(2* 1) \\\sf x= (5\pm\pl√(25+28))/(2) \\\boxed{\sf x= (5\pm\pl√(53))/(2) }`

Have a nice day ;)

Answer 2

Hello!

it's a quadratic equation

x = (-b ± √(b² - 4ac))/2a

= (-(-5) ± √((-5)² - 4*1*(-7)))/(2*1)

= (5 ± √(25 + 28))/2

= (5 ± √53)/2