149k views
5 votes
What are the exact solutions of x2 - 5x-7= 0, where

Ox=
O
x=
X
H
-5± √3
2
5+√3
2
-5± √53
2
5± √53
2
X=
-b± √b²-4ac7
2a

What are the exact solutions of x2 - 5x-7= 0, where Ox= O x= X H -5± √3 2 5+√3 2 -5± √53 2 5± √53 2 X-example-1
User Kirkegaard
by
8.0k points

2 Answers

4 votes

Hello !

Answer:


\large \boxed{\sf x= (5\pm\pl√(53))/(2) }

Explanation:

This equation is a quadratic equation in the form ax²+bx+c=0

The solution of this equation is given by the quadratic formula :


\sf x=(-b\pm√(b^2-4ac))/(2a)

Here we have :

  • a = 1
  • b = +5
  • c = -7

Let's replace a, b and c with their values in the quadratic formula :


\sf x=(-(-5)\pm√((-5)^2-4*1*(-7)))/(2* 1) \\\sf x= (5\pm\pl√(25+28))/(2) \\\boxed{\sf x= (5\pm\pl√(53))/(2) }

Have a nice day ;)

User David Brunow
by
8.2k points
4 votes

Hello!

it's a quadratic equation

x = (-b ± √(b² - 4ac))/2a

= (-(-5) ± √((-5)² - 4*1*(-7)))/(2*1)

= (5 ± √(25 + 28))/2

= (5 ± √53)/2

User Arpan Das
by
8.3k points
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