Question

a 3-digit security code can use numbers 0-9. how many possible combinations are there if the numvers can be repeated?

Answer 1

Since each digit can take on 10 possible values (0-9), and there are three digits in the code, we can find the total number of possible combinations by multiplying the number of options for each digit:

10 x 10 x 10= 1000

Therefore, there are 1000 possible combinations for a 3-digit security code if the numbers can be repeated.