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If sec 50 = cosec 70, prove that 0 = 7.5°​
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If sec 50 = cosec 70, prove that 0 = 7.5°​

User Stephen Klancher
by
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8 votes

Answer:

The proofing is given below:

Explanation:


Sec 5\theta = cosec 7\theta\\\\cosec (90 - 5\theta) = cosec 7\theta\\\\Now\ on\ comparision \\\\90 - 5\theta = 7\theta\\\\90 = 7\theta + 5\theta\\\\90 = 12\theta\\\\(90)/(12) = \theta\\\\0.75 = \theta

Hence, it is proved

If sec 50 = cosec 70, prove that 0 = 7.5°​-example-1
User Ahamed Moosa
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