Answer:
1,000 codes possible (check if my assumptions are correct)
Explanation:
Assuming that the code consists of 3 numbers from 0-9, in each digit there are 10 possibilities. Since there are no restrictions regarding repetition in the code, we can take the possibilities for each digit (10) and raise it to the power of the total number of digits (3), which gives us 1,000 total codes possible.