To determine the speed of the water balloon when it hits the ground, we can use the principles of kinematics and the equation for free-fall motion.
Assuming no air resistance, the acceleration due to gravity is approximately 9.8 m/s². We can use this value to calculate the speed of the water balloon.
The equation for the final velocity (v) in free-fall motion is given by:
v = √(2gh)
where:
v is the final velocity,
g is the acceleration due to gravity (9.8 m/s²),
h is the height from which the object is dropped.
Given that the height (h) is 20 m, we can substitute these values into the equation:
v = √(2 * 9.8 m/s² * 20 m)
v = √(392 m²/s²)
v ≈ 19.8 m/s
Therefore, the speed of the water balloon when it hits the ground is approximately 19.8 m/s.