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if an isotope has a cycle (half-life) of 2,000 years, approximately what percent of an original amount will remain after 6,000 years

User Eleazar
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1 Answer

4 votes

Answer: 12.5%

Explanation:

Formula for Half Life

N = N₀
((1)/(2) ^{(t)/(t_(1/2) ) } )

N = number of isotopes after

N₀ = Initial Isotopes

t = number of years


t_(1/2) = half life years

Given

t=6000


t_(1/2) = 2000

Percent is part out of the whole = remaining/starting amoung

Percent fraction =
(N)/(N_(0) )


(N)/(N_(0) ) = (1)/(2) ^{(t)/(t_(1/2) ) }


(N)/(N_(0) ) = (1)/(2) ^{(6000)/(2000 ) }


(N)/(N_(0) ) = .125 =12.5%

User BTMPL
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