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The cooling system of a car engine contains 20.0 l of water (1 l of water has a mass of 1 kg). what is the change in the temperature of the water if the engine operates until 836.0 kj of heat is added?

User Shrawan
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Answer:

To determine the change in temperature of the water in the car engine's cooling system, we can use the specific heat capacity formula:

Q = mcΔT

where Q is the heat energy absorbed or released, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.

Given the following values:

Mass of water (m) = 20.0 kg (1 l of water has a mass of 1 kg)

Heat energy (Q) = 836.0 kJ (kilojoules)

Specific heat capacity of water (c) = 4.18 kJ/kg·°C (approximate value)

Converting the heat energy from kilojoules to joules:

Q = 836.0 kJ × 1000 J/kJ = 836000 J

Now we can rearrange the formula to solve for ΔT:

ΔT = Q / (mc)

ΔT = 836000 J / (20.0 kg × 4.18 kJ/kg·°C)

Calculating the change in temperature:

ΔT ≈ 100°C

Therefore, the change in temperature of the water in the car engine's cooling system is approximately 100°C.

Step-by-step explanation:

User FMCorz
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