Answer:
To calculate the molarity (M) of the NaOH solution, you can use the concept of stoichiometry and the equation:
M₁V₁ = M₂V₂
where M₁ and V₁ are the molarity and volume of the H2SO4 solution, and M₂ and V₂ are the molarity and volume of the NaOH solution.
Given the following values:
M₁ = 1.50 M (molarity of H2SO4 solution)
V₁ = 40.00 ml (volume of H2SO4 solution)
V₂ = 25.00 ml (volume of NaOH solution)
Let's substitute the values into the equation and solve for M₂:
(1.50 M) × (40.00 ml) = M₂ × (25.00 ml)
M₂ = (1.50 M × 40.00 ml) / 25.00 ml
M₂ = 2.40 M
Therefore, the molarity of the NaOH solution is 2.40 M.
Step-by-step explanation: