Question

Hello

5.
What is the equation of a line that goes through the point (0, -3/5) and has a slope of -1?


y=-x-3/5


y=x-3/5


y=-3/5x-1


-3/5y=-x

please its urgent !!!

Answer 1

`(\stackrel{x_1}{0}~,~\stackrel{y_1}{-(3)/(5)})\hspace{10em} \stackrel{slope}{m} ~=~ - 1 \\\\\\ \begin{array}c \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-(3)/(5))}=\stackrel{m}{- 1}(x-\stackrel{x_1}{0}) \implies y +\cfrac{3}{5} = - 1 ( x -0) \\\\\\ y+\cfrac{3}{5}=-x\implies y=-x-\cfrac{3}{5}`

Answer 2

y = -x-3/5

Explanation:

Pre-Solving

We are given that a line goes through the point (0, -3/5) and has a slope (m) of -1.

We want to find the equation of this line.

Notice how the answers are written in slope-intercept form, which is y=mx+b, where m is the slope and b is the value of y at the y-intercept.

Solving

As we are given the slope, we can immediately plug that into the equation.

Substitute m as -1.

y = -1x + b

We can rewrite it to become:

y = -x + b

Now, notice that (0, -3/5), the point we are given is the y-intercept of the line (as the value of x is 0).

So, substitute -3/5 as b in the equation.

y = -x-3/5

The answer is the first one :).