Okay, let's solve this step-by-step:
* We are given that the initial volume of the gas is 1.75 L at 1 atm pressure
* We want to know the pressure if the volume increases to 16.60 L
* According to Boyle's Law: Pressure x Volume = Constant
* Since the initial pressure is 1 atm and volume is 1.75 L, the constant is:
1 atm x 1.75 L = 1.75 atm*L
* When the volume increases to 16.60 L, plugging into Boyle's Law:
P x 16.60 L = 1.75 atm*L
* Solving for P (pressure):
P = 1.75 atm*L / 16.60 L
P = 0.105 atm
Therefore, the pressure of the 1.75 L of disulfur monoxide gas if it occupied a volume of 16.60 L would be 0.105 atm.