A balloon was inflated to a volume of 5l at a temperature of 280 k. the balloon is heated to 420k. what is the new volume? v1/t1=v2/t2

Question

asked Feb 26, 2024 158k views

1 Answer

Peolss · Answer 1 · 2024-03-03T21:36:05+0000

Step-by-step explanation:

You are given the equation to use and all of the numbers except the one you are looking for....just plug-n-play

5/280 = v2/420

v2 = 420 * 5 / 280 = ?? liters