Question

New problem. suppose we have two positively charged particles a distance of 2 m apart from

each other. particle 1 has a charge of 3 c and particle 2 has a charge of 1.3 x 10^3 c. what
amount of electrostatic force exists between these two particles?
8.7 x 10^12 n
3.51 x 10^13 n
1.3 x 10^3 n

Answer 1

The force between two charged particles can be calculated using Coulomb's law, which states:

F = k * |q1*q2| / r^2

where:

F is the force between the charges,

q1 and q2 are the magnitudes of the charges,

r is the distance between the charges, and

k is Coulomb's constant, approximately 8.99 x 10^9 N m^2/C^2.

Given the charges q1 = 3C and q2 = 1.3 x 10^3 C, and the distance r = 2m, we can plug these values into the formula:

F = 8.99 x 10^9 N m^2/C^2 * |3C * 1.3 x 10^3 C| / (2m)^2

= 8.99 x 10^9 N m^2/C^2 * 3.9 x 10^3 C^2 / 4 m^2

= 8.99 x 10^9 N m^2/C^2 * 9.75 x 10^2 C^2 / m^2

= 8.74 x 10^12 N

Therefore, the amount of electrostatic force that exists between these two particles is approximately 8.74 x 10^12 N. The closest option to this calculation is 8.7 x 10^12 N, which might be due to rounding or significant figures.