Question

the position of an object on a velocity time graph is given as (20,5) and (10,3). calculate the acceleration of the object​

Answer 1

Alright so since these points are on the velocity-time graph, the first number in the bracket (in the place of the x axis) is time, and the second number in the bracket (in the place of the y axis) is velocity

Now I don’t know if you mistyped the points in like that instead of (5,20) and (3,10) or not because that would make more sense than what you sent, but I’ll solve both cases

Case 1:

Using (20,5) (10,3)
As we said, first numbers are time values, second numbers are velocity values
t1 = 10s and t2 = 20s
v1 = 3m/s and v2 = 5 m/s

Using the formula a = (v2 - v1)/(t2 - t1)
a = (5-3)/(20-10) = 2/10 = 0.2 m/s^2

Case 2:

If we use (5,20) and (3,10)

t1=3s and t2=5s
v1=10m/s and v2=20m/s

Using the same formula
a= (20-10)/(5-3) = 10/2 = 5m/s^2

Hope this helps

Answer 2

The acceleration of the object based on the velocity-time graph points (20,5) and (10,3) is 5 units per second squared, calculated using the change in velocity divided by the change in time.

Step-by-step explanation:

To calculate the acceleration of an object using a velocity-time graph, we need to consider the change in velocity (Δv) and the change in time (Δt). The points given are (20, 5) and (10, 3), which represent the velocity (in units of measurement per second) and time (in seconds), respectively. To find the acceleration, we use the formula:

a = Δv/Δt

First, we find the change in velocity:

Δv = v2 - v1 = 10 - 20 = -10 units/second

Then, we find the change in time:

Δt = t2 - t1 = 3 - 5 = -2 seconds

Now, we can calculate the acceleration:

a = -10 units/second / -2 seconds = 5 units/second²

The negative signs cancel each other out, so the acceleration of the object is 5 units per second squared.