Question

A gas with volume of 425 ml has a temperature of 67 c. what will the volume be at -10c?

Answer 1

`\huge\boxed{\sf V_2 = 382.75 \ ml}`

Step-by-step explanation:

Given data:

Volume 1 =
`V_1` = 425 ml

Temperature 1 =
`T_1` = 67°C + 273 = 340 K

Temperature 2 =
`T_2` = -10°C + 273 = 263 K

Required:

Volume 2 =
`V_2` = ?

Formula:

`\displaystyle (V_1)/(T_1) = (V_2)/(T_2)` (Charles Law)

Solution:

Put the given data in the above formula.

`\displaystyle (425)/(340) = (V_2)/(263) \\\\Cross \ multiply\\\\425 * 263 = V_2 * 340\\\\111775 = V_2 * 340\\\\Divide \ both \ sides \ by \ 340\\\\111775/340 = V_2\\\\382.75 - V_2\\\\V_2 = 382.75 \ ml\\\\\rule[225]{225}{2}`