Question

A gas occupies 11. 2 liters at 0. 860 atm. What is the pressure if the volume increased by 4?

Answer 1

`\huge\boxed{\sf P_2 \approx 0.63\ atm}`

Step-by-step explanation:

Given data:

Pressure 1 =
`P_1` = 0.860 atm

Volume 1 =
`V_1` = 11.2 L

Volume 2 =
`V_2` = 15.2 L

Required:

Pressure 2 =
`P_2` = ?

Formula:

`V_1P_1=V_2P_2` (Boyle's Law)

Solution:

Put the given data in the above formula.

(11.2)(0.860) = (15.2)(P₂)

9.632 = (15.2)(P₂)

• Divide both sides by 15.2

9.632 / 15.2 = P₂

P₂ ≈ 0.63 atm

`\rule[225]{225}{2}`