Question

help me please all this is to confused to me so if anyone can help me with each question i will give brainy as long as they give me actual answers to each question please.

Answer 1

Answer to Q3:

b = 6

Term you are adding to both sides = 9

x = ± 25 - 3

Explanation:

The equation is already rewritten in the form:

x² + bx = c

x² + 6x = 16

b = 6

To complete the square, find half of b, square it, and add it to both sides of the equation.

`((b)/(2))^2` =
`((6)/(2))^2` = 3² = 9

x² + 6x + 9 = 16 + 9

x² + 6x + 9 = 25

Rewrite the left side of the equation as a squared term.

x² + 6x + 9 = 25

(
`\sqrt{x^(2)+9 }`)² = 25

(x + 3)² = 25

Take the square root of both sides.

x + 3 = ± 25

Make x the subject.

x = ± 25 - 3

Answer 2

Explanation:

b=3²=9

x²+2×x×3+9=16+9

(x+3)²=25

(x+3)²-5²=0

(x+3-5)(x+3+5)=0

(x-2)(x+8)=0

either x-2=0. OR x+8=0

so, x=2 or 8