If 119 J of work is done in pushing a box horizontally 17 m, we can use the work-energy principle to find the force applied. The work-energy principle states that the work done on an object is equal to the change in its kinetic energy. Since the box is initially at rest, the work done on it is equal to its final kinetic energy, which is given by:
(1/2)mv^2
where m is the mass of the box and v is its final velocity. Since the box is pushed horizontally, the force applied is in the same direction as the displacement, so the work done is given by:
W = Fd
where F is the force applied and d is the displacement. Setting these two expressions equal to each other, we get:
Fd = (1/2)mv^2
Solving for F, we get:
F = (1/2)(m/d)v^2
We are not given the mass of the box or its final velocity, but we can use the fact that the work done is 119 J and the displacement is 17 m to find the force applied. Plugging in the given values, we get:
F = (1/2)(119 J / 17 m) = 3.5 N
Therefore, the force applied is 3.5 N.