Question

An object moving with a speed of 108km/h stops in 15s due to auniform acceleration.Find the value of the acceleratiin.​

Answer 1

First, we need to convert the speed from km/h to m/s to use it in the equation. We have:

108 km/h = 30 m/s (approx)

The formula for acceleration is:

a = (v_f - v_i) / t

where a is the acceleration, v_f is the final velocity, v_i is the initial velocity, and t is the time taken. We know the initial velocity is 30 m/s (since the object is moving with a constant velocity before it starts to decelerate), the final velocity is 0 m/s (since the object comes to a stop), and the time taken is 15 s. Substituting these values into the formula, we get:

a = (0 - 30) / 15 = -2 m/s^2

The negative sign indicates that the acceleration is in the opposite direction to the initial velocity, which is deceleration. Therefore, the value of the acceleration is 2 m/s^2.

Answer 2

First you need to write your given information. Vi(initial velocity) = 108 km/h = 30m/s (divide km/h by 3.6 to convert it to m/s)
Vf (final velocity) = 0 m/s (because it stops)
Δt(time)=15 s
a (acceleration) = ?

The rule for acceleration is
a= (Vf - Vi)/Δt
Substitute
a= (0-30)/15 = -30/15 = -2 m/s^2

Hope this helps