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A sample of water weighing 523g is cooled by 23C. Calculate the q value for this process.

User Tyren
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1 Answer

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Answer:

The q value for this process is -241.69 kJ.

Step-by-step explanation:

To calculate the q value, we need to use the equation:

q = m * c * ΔT

where:

q is the heat energy absorbed or released,

m is the mass of the substance,

c is the specific heat capacity of the substance,

ΔT is the change in temperature.

In this case, the mass of the water (m) is given as 0.523 kg, the change in temperature (ΔT) is 23°C, and the specific heat capacity of water (c) is approximately 4.18 kJ/kg°C.

Substituting the values into the equation:

q = 0.523 kg * 4.18 kJ/kg°C * 23°C

q = 5.46 kJ * 23°C

q = -125.58 kJ

The negative sign indicates that heat is being released from the water as it cools. Therefore, the q value for this process is -125.58 kJ or approximately -241.69 kJ (rounded to two decimal places).

User Chere
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