Question

If x-y =12 and y^2 =5 (x-2), what are two possible values of y

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Answer 1

From the first equation, we can rearrange to get x = 12 + y.

Substituting that into the second equation, we get y^2 = 5(12 + y - 2) = 50 + 5y.

This simplifies to y^2 - 5y - 50 = 0.

Using the quadratic formula, we can solve for y to get y = 10 or y = -5.

Therefore, two possible values of y are 10 and -5.