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Find the standard deviation for each data set. Use the standard deviations to compare the pair of data sets.

fastest recorded speeds of various large wild cats (miles per hour):
65 40 25 45 40 35 35 50 20
fasted recorded speeds of various birds in flight (miles per hour):
219 104 96 57 67 38 50 31 51 25 30 25

User Gkrishy
by
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1 Answer

3 votes

Answer:

Explanation:

you didn't really specificy so i will just calculate the sample standard deviations. if it says that the standard deviations are wrong or you were supposed to use the population standard deviation formulas then the answers will be slightly different

sqrrt(sum(x-avg)^2)/(n-1)

average for wildcats

(65+40+25+45+40+35+35+50+20)/9= 39.4444444444


\sqrt{(65-39.4444)^2+(40-39.4444)^2+(25-39.4444)^2+(45-39.4444)^2...\\$\\√(1422.2222222222222/8)= 13.3333333333333

Average for birds

(219+104+96+57+67+38+50+31+51+25+30+25)/12= 66.083333

stdev= 54.75807675

The standard deviation for birds is much higher compared to the wildcats. This means that birds the speed at which birds are able to fly varies a lot from bird to bird.

User Anton Danilov
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8.1k points