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Angle theta is in standard position and (-7, 6) is a point on the terminal side of theta.

What is the exact value of csc in simplest form with a rational denominator?

User Picus
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To find the exact value of the cosecant (csc) of an angle in standard position with a given point on its terminal side, we can use the coordinates of the point to determine the values of the adjacent, opposite, and hypotenuse sides of a right triangle.

In this case, the given point is (-7, 6). To determine the values of the sides, we can use the Pythagorean theorem.

The adjacent side (x-coordinate) is -7.

The opposite side (y-coordinate) is 6.

Using the Pythagorean theorem:

hypotenuse^2 = adjacent^2 + opposite^2

hypotenuse^2 = (-7)^2 + 6^2

hypotenuse^2 = 49 + 36

hypotenuse^2 = 85

Taking the square root of both sides, we get:

hypotenuse = √85

The cosecant (csc) of an angle is the reciprocal of the sine (sin) of that angle. The sine can be determined using the opposite side and the hypotenuse:

sin(theta) = opposite / hypotenuse

sin(theta) = 6 / √85

To find the csc(theta), we take the reciprocal of the sine:

csc(theta) = 1 / sin(theta)

csc(theta) = 1 / (6 / √85)

csc(theta) = √85 / 6

Therefore, the exact value of csc(theta) with a rational denominator is √85 / 6.

User Panagiotis Simakis
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