Question

in how many ways can first , second , and third prizes be awarded in a cont with 925 contestants? assume there is no ties

Answer 1

To determine the number of ways the first, second, and third prizes can be awarded in a contest with 925 contestants, we can use the concept of permutations.

For the first prize, there are 925 contestants eligible to win. After the first prize is awarded, there are 924 remaining contestants for the second prize. Finally, for the third prize, there are 923 remaining contestants.

The number of ways to award the prizes can be calculated as the product of the number of choices for each prize:

Number of ways = 925 * 924 * 923

Calculating this expression, we find:

Number of ways = 779,449,100

Therefore, there are 779,449,100 ways to award the first, second, and third prizes in the contest with 925 contestants.

Answer 2

Explanation:

`(925!)/((925-3)!)= 923*924*925=788,888,100`