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Simplify Square root of x^2-8x+16 if x<4

User Halena
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If x < 4, then x - 4 is negative, and we cannot take the square root of a negative number. Therefore, the expression is undefined for x < 4.

If x = 4, then the expression becomes:

sqrt(4^2 - 8(4) + 16) = sqrt(16 - 32 + 16) = sqrt(0) = 0

If x > 4, then we can simplify the expression as follows:

sqrt(x^2 - 8x + 16) = sqrt((x - 4)^2) = |x - 4|

Therefore, the simplified expression is |x - 4| for x > 4, and it is undefined for x < 4.
User Dmagda
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