Question

Please help me solve this

Answer 1

Answer: ( z + 3q ) ( z^2− 3zq + 9q^2 )

Step-by-step explanation:

Problem z3+27q3z3+27q3

SolutionSince both terms are perfect cubes, factorusing the sum of cubes formula,

a3 + b3 = (a + b) (a2 − ab + b2) a3+ b3 = (a + b) (a2 - ab + b2) where a = z and b = 3q

( z + 3q ) ( z^2− 3zq + 9q^2 )

Answer 2

(z + 3)(z^2 - 3z + 9)

Explanation:

To factor the expression z^3 + 27 completely, we can use the sum of cubes formula. The sum of cubes formula states that a^3 + b^3 can be factored as (a + b)(a^2 - ab + b^2). In this case, a = z and b = 3.

Applying the sum of cubes formula, we have:

z^3 + 27 = (z + 3)(z^2 - 3z + 9).

Therefore, the expression z^3 + 27 can be factored completely as (z + 3)(z^2 - 3z + 9).