123k views
0 votes
Help pleasessssssss !

An automobile, whose speed is increasing at a rate of 0.6m / (s ^ 2) , travels along a circular road of radius 20m. What will be automobile's angular acceleration when its instantaneous speed of the automobile is 4 m/s? ​

1 Answer

5 votes
We can start by finding the magnitude of the automobile's centripetal acceleration using the formula:

a = v^2 / r

where v is the instantaneous speed of the automobile and r is the radius of the circular road. Plugging in the given values, we get:

a = (4 m/s)^2 / 20 m = 0.8 m/s^2

The centripetal acceleration is related to the angular acceleration by the formula:

a = r * alpha

where alpha is the angular acceleration. Solving for alpha, we get:

alpha = a / r = 0.8 m/s^2 / 20 m = 0.04 rad/s^2

Therefore, the automobile's angular acceleration is 0.04 rad/s^2 when its instantaneous speed is 4 m/s.
User Sargturner
by
7.4k points