Question

A 115 N object vibrates with a period of 5 seconds when hanging from

spring. What is the spring constant of the spring?

Answer 1

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Answer 2

The spring constant k can be calculated using the formula T = 2π * sqrt(m/k), where T is the period of vibration and m is the mass of the object. Since the weight of the object is given as 115 N, we can calculate its mass as m = F/g, where F is the weight and g is the acceleration due to gravity (9.8 m/s^2). Plugging in the values, we get m = 115 N / 9.8 m/s^2 = 11.73 kg. Now we can solve for k using the formula above: 5 s = 2π * sqrt(11.73 kg / k). Solving for k, we get k ≈ 1.8 N/m.

Received message. The spring constant `k` can be calculated using the formula `T = 2π * sqrt(m/k)`, where `T` is the period of vibration and `m` is the mass of the object. Since the weight of the object is given as 115 N, we can calculate its mass as `m = F/g`, where `F` is the weight and `g` is the acceleration due to gravity (9.8 m/s^2). Plugging in the values, we get `m = 115 N / 9.8 m/s^2 = 11.73 kg`. Now we can solve for `k` using the formula above: `5 s = 2π * sqrt(11.73 kg / k)`. Solving for `k`, we get `k ≈ 1.8 N/m`.