How many moles are in 33 grams of Boron (B)?

asked Nov 9, 2023 58.4k views

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by CXL

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10 votes

Answer:

2.77495 moles

Step-by-step explanation:

Boron= 10.811g (according to periodic table)

33g*(1mole)/(10.811g B)=2.774951 moles B

Uri Meirav answered Nov 14, 2023

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