Answer:
d) 2
Step-by-step explanation:
We are given;
n = 4, l = 1, m = -1
We can tell that is is an orbital with sub shell as 3P.
Now, from Paul's exclusion principle, each orbital will have maximum of 2 electrons of each π with a spin of +½ and -½.
Since the maximum is seen to be 2, then option D is correct.