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Geometry Help!

Hi there! Need a little help with this question:

in a given diagram below, ray AB bisects angle FAE. BF=2x+8 and BE=42
(The diagram will be attached.)

Could someone explain this to me in detailed, but easy to understand steps? I'm a bit of a slow learner when it comes to math, haha..

Geometry Help! Hi there! Need a little help with this question: in a given diagram-example-1
User Mavershang
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2 Answers

1 vote

Answer:

x=17

Explanation:

Ok, so let's start with what we're given. We know that BF=2x+8, and this is a line segment that goes through A F and AB. We also know that BE is 42, but also goes through line segments AE and AB. As you can see, both segments BF and BE go through the line segment AB, which is an angle bisector.

An angle bisector is a line segment that cuts the angle perfectly in half. For an example, let's say that angle FAE is 50°. This means that angle 1 and 2 are both 25°.

But now that we know an angle bisector cuts the angle perfectly in half, we now know that BF and BE have to be congruent (equal) to each other. This means we can set up an equation:

2x+8=42

subtract 8 from both sides

2x=34

divide both sides by 2

x=17.

So, x=17.

I hope this helps you better understand! :)

User Magohamote
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7.8k points
4 votes

Answer: the answer is 48

Explanation:

I dont know who removed my answer but the next time you do it we're gonna have a problem best believe ⇄

User Ronkov
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7.6k points