Based on the given wavelength of 6.5 × 10-10, we can determine the following:
The type of wave: C) ultraviolet
Ultraviolet waves have shorter wavelengths than visible light and are categorized between X-rays and visible light in the electromagnetic spectrum.
The frequency of the wave: 4.62 × 10^17
Frequency (f) is inversely proportional to wavelength (λ) and can be calculated using the equation: f = c / λ, where c is the speed of light (~3 × 10^8 m/s). Substituting the values, we have f = 3 × 10^8 / (6.5 × 10^-10) = 4.62 × 10^17 Hz.
The energy of a photon of this electromagnetic wave: 1.24 × 10^-16
The energy (E) of a photon can be calculated using the equation: E = hf, where h is Planck's constant (6.626 × 10^-34 J·s). Substituting the values, we have E = (6.626 × 10^-34) × (4.62 × 10^17) ≈ 1.24 × 10^-16 J.
Compared to a beam of red light, the photons in this electromagnetic wave would be traveling: C) slower than the red light photons
The speed of light in a vacuum is constant for all electromagnetic waves, so the speed of ultraviolet photons is the same as the speed of red light photons.
Compared to the wavelength of a beam of red light, the wavelength of these electromagnetic waves would be: C) smaller
Ultraviolet waves have shorter wavelengths than red light in the visible spectrum.